Here are today’s CHM 100 notes.  These notes discuss how to round the amswers of multiplying and dividing measurements.  They also cover how to write numbers in scientific notation and how to enter scientific notation into a TI-83 (or similar) calculator.

[CHM 100: 2/2/09 notes]

Here are yesterday’s CHM 111 notes.  These notes discuss the classification of solids by structure and the units for calculating the concentration of a solution.

[CHM 111: 1/28/09 notes]

Here are today’s CHM 100 class notes.  These notes cover how to deal with the number zero in measurements and how to round answers when adding measured numbers.

[CHM 100: 1/28/09 notes]

Here are today’s class notes.  These notes cover intermolecular forces in liquids and how they affect liquid properties.  They also cover the kinds of forces present in the solid state.

[CHM 111: 1/26/09 notes]

Here are today’s CHM 100 notes.  These notes cover a few more dimensional analysis examples, then introduce accuracy, precision, and the concept of significant figures.

[CHM 100: 1/26/09 notes]

Here are the notes from Wednesday’s CHM 111 class. These notes continue our discussion of valence bond theory from Chapter 10, then introduce the phases of matter from Chapter 11.

[CHM 111: 1/21/09 notes]

We discusses several chlorine-containing hydrocarbons during our talk about how double bonds work in valence bond theory.  Here they are.

This is 1,2 dichloroethane. Both ends of this molecule are free to rotate around the C-C bond.

This is cis 1,2-dichloroethene. Both of the chlorine atoms are on the same side of the C=C bond. The chlorine atoms are fixed in this position because the double bond does not allow free rotation, since rotation would break the pi component of the double bond. This illustration shows electrostatic potential, and we can see that this molecule is polar.

This is trans 1,2-dichloroethene. The chlorine atoms are on opposite sides of the C=C bond. The chlorine atoms are fixed in this position because the double bond does not allow free rotation, since rotation would break the pi component of the double bond. This illustration shows electrostatic potential, and we can see that this molecule is nonpolar. It also has observably different physical properties (like boiling point) from the cis form.

Here are the notes from today;s CHM 100 class.  These notes discuss how to convert between units with dimensional analysis.

[CHM 100: 1/21/09 notes]